In 2023 the best (smallest) device size that can be put on a chip has dimensions of about 2nm. The design for a bit of memory that requires the fewest transistors needs two. How much memory could fit into the chip, assuming it contains only memory? First, we’ll calculate the maximum number of devices that will fit, M.
That yields M=125 devices. If it takes 2 devices to make one bit of memory, then the maximum number of bits, B, (again, the whole chip is memory) is
Let’s call that 63 bits. There are eight bits in one byte. Thus, that’s a little less than eight total bytes. Not eight giga, mega, or even kilobytes, eight (8) total bytes.
With only eight bytes available, that has consequences for the capabilities of the chip — though it should be obvious that that the chip is already impossible — and one of them is that anything the chip tries to report back to the GWF must be sent out in clear text. It can’t be encrypted, because eight bytes of memory simply isn’t enough memory to hold any encryption algorithm. So, if the chip tries to say, “Sally just ate a pizza”, anyone with a receiver can intercept that signal and read it. That’s bad since it’s imperative that the chip not be detected.
Remember, we just calculated eight bytes assuming the chip was entirely memory. If only one-quarter of the chip is memory, that’s two bytes. And that’s practically nothing.
Suppose the only goal of the chip is to give each patient an identifier. Using the entire chip to store the identifier (leaving no power supply, no detector, no microcontroller, no antenna…) eight bytes would be more than enough to assign a unique ID. If one-quarter of the chip is used to store the ID, that’s only two bytes, which is 65536 IDs. If the plan is to vaccinate 200 million people, then there are 3051 people for each ID. But that doesn’t help much. How does the GWF know which ID belongs to whom? The GWF will have to employ a lot of people to figure out who got which ID, and if it’s not unique, what’s the point?